I have 2 integer in my structure
i hv to write a fixed length binary format in a text file. but what i dont understand is how to do this particular problem. For example, if the value of a is equal to 48, it must be stored as 48 (in decimal)Code:struct{ int a; int b; }
or 30 (in hexadecimal; in C: 0x30). It must not be stored as the string “48”,
occupying two bytes.
thanks
These two things are typically mutually exclusive....binary format in a text file...
Mainframe assembler programmer by trade. C coder when I can.
use fopen with "wb" mode to open file as binary
and fwrite to write a struct as binary
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
But, given that structure, if you're expecting say 00 48 to appear in the file as two bytes, then you need to do something yourself.
Writing the whole structure in one step, whilst possible, it not portable. There are padding, alignment and endian issues which may get in the way of the result you expect.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
