Thread: printinga number while being incrementing on the screen

  1. #1
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    printinga number while being incrementing on the screen

    Hi All
    How can i print/display a number being incremented on the screen. For example
    a variable 'i' is being incremented like this i = i+224, i would like to print this number on the screen while its being incremented something like below:


    224(then 448 etc)

    not like the below:

    224 448 672 etc
    Any help will highly be appreciated
    Regards

  2. #2
    Just Lurking Dave_Sinkula's Avatar
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    You may want to try a format such as "\r%d".
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

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    Quote Originally Posted by Dave_Sinkula View Post
    You may want to try a format such as "\r%d".
    Doesn't this format only display the total incremented number? i dont want to have that....

  4. #4
    Just Lurking Dave_Sinkula's Avatar
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    Then I have no idea what you are trying to say.
    Last edited by Dave_Sinkula; 03-26-2008 at 10:48 PM. Reason: Added -ing. Oops.
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

  5. #5
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    Quote Originally Posted by Dave_Sinkula View Post
    Then I have no idea what you are try to say.
    An example of what i am trying to accomplish here is, if you install a software and the progress bar increases and the % number being incremented on the screen displaying the % complete of installation. I would like to do something like that, to display the %number being incremented on the screen.

    Regardss

  6. #6
    Just Lurking Dave_Sinkula's Avatar
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    That's what I though, which is why I suggested trying this.
    Code:
    #include <stdio.h>
    
    int main()
    {
       int i;
       for ( i = 0; i < 100000 * 224; i += 224 )
       {
          printf("\r&#37;d", i);
       }
       return 0;
    }
    Whether or not that does what you want is up to the command shell to a large degree.
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

  7. #7
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    Quote Originally Posted by Dave_Sinkula View Post
    That's what I though, which is why I suggested trying this.
    Code:
    #include <stdio.h>
    
    int main()
    {
       int i;
       for ( i = 0; i < 100000 * 224; i += 224 )
       {
          printf("\r&#37;d", i);
       }
       return 0;
    }
    Whether or not that does what you want is up to the command shell to a large degree.
    This will not do it. Most likely!

    First there is no sleep or as such to allow us to see the increment. Then there is no '\n' printed so
    printf will buffer the output and will print unpredictably!
    There should be a sleep, and a flush call to make it work!

  8. #8
    Just Lurking Dave_Sinkula's Avatar
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    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

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