Thread: Array print problem

Ok, so i've got a bit of a problem. I've dynamically allocated a 2d array, grabbeb input and put it into a buffer, and now would like to print the output, but am having some trouble thus far.
Here is my code:

** Note: the variable size included in the malloc statement is a previously defined variable by the user ** just incase anyone was wondering why it was there

Code:

p = (char**)malloc(size*sizeof(char*));
   if (p == NULL) merror();
   for (j=0; j<size; j++) {
		p[j]=(char*)malloc(21);
		if (p[j] == NULL) merror();
		B: printf("Enter a name:");
		fflush(stdout);
			for(k=0; k<20; k++) {
			buffer[k]=fgetc(stdin);
				if (buffer[k]=='\n') {
				buffer[k]='\0';
			break;
       }
     }
     if (k==20) {
     printf("input too long\n");
     while(fgetc(stdin)!='\n');
     goto B;
   }
   if (buffer[0]=='\0') {
     printf("Empty input. Please re-enter\n");
     goto B;
   } 
 }
 // Here is where i need to print the output of words
 // Not too sure how to do this i.e., what for statements, and how to strcpy from the buffer to array and print it
   }
 
return 0;
 }

Any help is greatly appreciated

Well, I dont know how to use fgets() to count the input for a maximum of 20 characters, so i chose to use fgetc to do it character by character. I'm not sure what you mean by casting malloc, Im fairly new to C and programming in general, so I guess I will have to look that one up. As for the copying of the strings, I've been tryin to use strcpy, but I really am stuck on from what I need to copy. Im pretty sure my code is storing the names into a buffer, and I guess I need to copy from the buffer, into an array. Ive tried:

Code:

strcpy(store, buffer[k]);

However, I cannot get this...