Thread: Entry Level Help.

Ice Dane, I am a junior Electrical engineering student and this is the only programming course I have to take. We are on "loops" in the book and that is what is supposed to be used for the assignment. No arrays, just statements and loops. Let me remind you all this is an INTRO level course. Some of the stuff you guys have said isn't even in my book or is on the last few chapters. I will have the solution for program tomorrow and post it.

I think this board is a little to far advanced for me. You guys really know your stuff. Way out of my league. =)

> I believe enumerated constants start at 0 by default.
They do, and I pointed out your error.

Code:

int iLike;

printf("What fruit do you like?\n");
printf("1. Apple\n");
printf("2. Orange\n");
printf("3. Banana!\n");
printf("4. Lemon?\n");
scanf("%d", &iLike);
iLike++;   /* the enum constants start from 0 in this example */

If the user enters, 1 for apple. They then like 1 + 1 = 2 (Banana), Rather than 1 - 1 = 0 (Apple).

In short you increased iLike when you should have decreased it. That means you go out-of-bounds when you try to access a "Lemon" for example. It's name would then be... according to you fruitname[5] (out-of-bounds) -- No, it's fruitname[3]. Run it through a debugger and see for yourself.

> As for the test, it was purposefully written such that it demonstrates the readability of enum constants versus "magic" numbers.
No excuse for errors

Originally Posted by zacs7

> I believe enumerated constants start at 0 by default.
They do, and I pointed out your error.

True, i meant --

No excuse for errors

True. Compilers make errors, humans with a vast dislike for sleep almost never.