Thread: Problems with pointer to multidimensional array

I'm having some problems iterating through a bidimensional array,as I cn't print all the elements on a matrix form.Here's my code:

Code:

#include <stdio.h>
#include <string.h>
#define L1 3
#define C1 2
#define L2 4
#define C2 3

void escreve1(int mat[][C1],int lin, int col);
void escreve2(int mat[][C2],int lin, int col);

void main()
{
	int mat1[L1][C1]={{1,2},{3,4},{5,6}};
    int mat2[L2][C2]={{1,2,3},{4,5,6},{7,8,9},{10,11,12}};

    printf("\nMatriz mat1:\n");
    escreve1(mat1, L1, C1);
   printf("\nMatriz mat2:\n");
    escreve2(mat2, L2, C2);


}
void escreve1(int mat[][C1] , int lin, int col)
{
 int  *z;

	   for(z=mat[0];z<mat[0]+col*lin;z++)
	  {
	   
	   printf("&#37;d\t",*z );
	   if(z==mat[0]+(col-1))
		  printf("\n");
	   
	  }
	
  
   
   
}

void escreve2(int mat[][C2] , int lin, int col)
{


 int *z;

   
	  for(z=mat[0];z<mat[0]+col*lin;z++)
	  {
	    printf("%d\t",*z );
	   if(z==mat[0]+(col-1))
		  printf("\n");
	  }

I want the output to be something like this:

Code:

Matriz mat1:
   1 2
   3 4
   5 6

  Matriz mat2:
   1 2 3
   4 5 6
   7 8 9
   10 11 12

Any help is very appreciated!

PS:The output I'm getting is:

Code:

Matriz mat1:
   1 2
   3 4 5 6

  Matriz mat2:
   1 2 3
   4 5 6 7 8 9 10 11 12

It's easier if you don't use only pointers, then you can use % with the width.

I suppose you might get away with a ptrdiff, something like

Code:

/* caveat: http://c-faq.com/aryptr/ary2dfunc2.html */
void escreve1(int *mat, int lin, int col)
{
   int *z = mat;
   while ( z < &mat[lin * col] )
   {
      printf("%d%c", *z, (z - mat) % col == col - 1 ? '\n' : '\t' );
      ++z;
   }
}