but the prob is, that even maths contains conflicts between facts derived directly from axioms...

And brewbuck, I did not understand your questions, sorry :(

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- 04-16-2007hardi
but the prob is, that even maths contains conflicts between facts derived directly from axioms...

And brewbuck, I did not understand your questions, sorry :( - 04-16-2007hardi
We are creating laws that work in certain circumstances... But possibly, not in all...

- 04-16-2007Rashakil Fol
The 1/3 * s * h formula can be proven without calculus.

Consider the unit cube, with vertices (0,0,0), (0,0,1), through (1,1,1).

There are three faces that don't touch the origin. Connecting them to the origin forms three congruent cones (or pyramids, since they have square bases) with base area 1 and height 1 that fill up the volume of the cube.

Any other cones are formed by linear transformations and rearranging the bases' shapes. (The rearranging the bases' shapes part can be proven without going through all of calculus, too, but that depends on what your definition of 'area' and 'volume' are. And on how radically you're willing to rearrange bases' shapes.) - 04-16-2007brewbuck
Can you give an example?

Quote:

And brewbuck, I did not understand your questions, sorry :(

The real question is, "What does it mean to measure something?" - 04-16-2007Rashakil Fol
- 04-16-2007hardi
- 04-16-2007DavidP
I hate proofs with a passion.

- 04-16-2007hardi
I think this is an example(though i am not sure, maybe my definitions are errenous).

Given a straight line and a point, there is only one line that goes through that point and is parallel to the other line. (I think this is one of the axioms...).

In case we are talking about a sphere, then there can be no such thing... (ofcourse, nothing is derived here). Actually, i don't know of any good examples about colliding derivations. And maybe I missed out a part of the definition... - 04-16-2007brewbuck
Trying to apply such an axiom to the surface of a sphere is nonsensical. For one thing, you haven't defined "line" and "parallel" in the context of a sphere. A line on the surface of a sphere, when considered in a Euclidean space, isn't a line at all.

You see contradictions because the axioms have been (over) simplified. - 04-16-2007hardi
very possible - i just need to recheck them :D

- 04-16-2007Rashakil Fol
If you're doing geometry on the surface of a sphere, you're working with a different set of axioms. There's nothing contradicting, you're just working with a different set of axioms. That's like defining your own addition operator on the integers and saying there are conflicts in the axioms because what you've defined implies 2 + 2 = -4 while another definition of addition implies that 2 + 2 = 4.

- 04-16-2007hardi
yup, that axiom just doesn't work on a sphere.