I think what Bubba was referring was to Happy_Reaper's reply. Fixed points, not intersections.

It is obvious that both functions intersect at the fixed point since both functions cancel each other.Quote:

Originally Posted byBubba

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- 09-17-2006Mario F.
I think what Bubba was referring was to Happy_Reaper's reply. Fixed points, not intersections.

Quote:

Originally Posted by**Bubba**

- 09-17-2006psychopathQuote:

Originally Posted by**Bubba**

- 09-17-2006twomers
>> I wish you people would stop being so stuck-up and switch to metric.

Heh. I agree .... what was that quote ...

Grandpa Simpson: The Metric System is the tool of the devil! My car gets five rods to the hog's head and that's the way I likes it!

:p

BTW, there are worse things than pounds per square inch in mech eng!! - 09-18-2006Rashakil Fol
This always happens whenever you have a linear relationship of the form f(x) = mx + b, where m != 1. You'll find that f(x) = x when x = b/(1-m).

What you have are two linear functions that are inverses of each other (by design, since converting from Fahrenheit to Celcius to Fahrenheit should give you the same temperature), and since one has a fixed point, the inverse must have the same fixed point.

You'll find the same thing with, say, g(x) = 2x + 3 and h(x) = (1/2)(x-3).

Every non-constant linear function has an inverse function, and they'll always have the same effect.