# mathematics <exponential>

This is a discussion on mathematics <exponential> within the A Brief History of Cprogramming.com forums, part of the Community Boards category; I understand that the following. approximately e=2.71828182845904523536 I have been asked in my mathematics book to graph e on my ...

1. ## mathematics <exponential>

I understand that the following.

approximately
e=2.71828182845904523536

I have been asked in my mathematics book to graph e on my calculator.

How would I do this?
It does not ask me to graph e^x.
Just e by itself.
What would that be on my calculator (TI-85)?

I have been unable to find this through google as of yet.

2. e = lim n->infinity (1 + 1/n)^n
http://mathforum.org/dr.math/faq/faq.e.html

y = (1 + 1/x)^x

3. I know that it has that as the function.
let me tell you the full problem.
I must be completely misunderstanding this.
please forgive the simplicity of the question.

[text problem]
Illustrate the definition of the number e by graphing the curve y=(1+(1/n))^x and the line y=e on the same screen using the viewing rectangle [0,40] by [0,4].
[/text problem]

Understand everything on this problem except the line y=e?
I have already graphed (1+(1/n))^x, but I'm not sure what they want by y=e.

to me i would say
e=(1+(1/n))^x
so it would be the same line.
but how would i prove that with a graphing calculator
and how would i graph e

4. e is a number, what do you get when you have y=1? You have a horzontal line crossing (0,1). So push into your calculator y = e. If you only have a e^ key then either delete the ^ symbol or put in e^1.

I mean they told you exactly what they wanted.

e=(1+(1/n))^x
This is not correct. e only equals this formula at the limit as n becomes unbounded.

5. i didn't know you could delete portions of a predefined function on the calculator.
deleting the ^ from e^ drew a line at just about 3.
so that worked.
thanks thantos.

6. umm y=e^1?

7. I'm pretty sure they wanted you to illustrate the convergence of e as e approaches infinity compared to a (relatively accurate) approximation of e .

As Thantos said, just put y=(1+1/x)^x and y=e^1.

8. Why bump a 4 day old thread when the OP has already stated that they have it working?