Nothing to do with C++Originally Posted by xviddivxoggmp3
exp(x) = e^x = 2.71828...^x
And yes, that step is valid, but the next step is illegal, the correct step would be something like:
-pi = pi + 2*n*pi
This is a discussion on Mathematics Odd/Even Functions within the A Brief History of Cprogramming.com forums, part of the Community Boards category; Originally Posted by xviddivxoggmp3 is this valid? I have very little experience with complex numbers in C++. Isn't there a ...
Nothing to do with C++Originally Posted by xviddivxoggmp3
exp(x) = e^x = 2.71828...^x
And yes, that step is valid, but the next step is illegal, the correct step would be something like:
-pi = pi + 2*n*pi
Last edited by Sang-drax : Tomorrow at 02:21 AM. Reason: Time travelling
It depends on how you define logarithm. I could define ln for a complex number z to be:Originally Posted by Zach L.
ln z = ln|z| + i*arg(z) , (0<=arg(z)<=2*pi)
Then e^ln(z) = z for all complex numbers z
I guess that could be one definition.
EDIT:
http://www.efg2.com/Lab/Mathematics/...sAndPowers.htm
Last edited by Sang-drax; 10-18-2004 at 05:05 PM.
Last edited by Sang-drax : Tomorrow at 02:21 AM. Reason: Time travelling
Nifty... Makes sense.
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