If we're putting these values in a binary tree. 8,7,6,5,4,3,2,1, it will be an ordered tree. It will look like an unbalanced tree with all the node on the left side. The search efficiency will be big-Oh(n), right? Well, suppose we have a balance tree. 4 is the root and it's balance. According to my source, the worst code big-Oh is now O(log(n)). How is that? Isn't it Omega(log(n))? Couldn't the worst case for a binary tree still be O(n)? What if in searching the element in a tree is a leaf node all the way at the left-end? The search efficiency would be O(n) woulnd't it, not O(log(n))?