a=b
a^2 = ab
a^2-b^2 = ab-b^2
(a+b)(a-b) = b(a-b)
(a+b)=b
(a+a)=a
2a = a
2 = 1
valid?
This is a discussion on 2=1, is this valid? within the A Brief History of Cprogramming.com forums, part of the Community Boards category; a=b a^2 = ab a^2-b^2 = ab-b^2 (a+b)(a-b) = b(a-b) (a+b)=b (a+a)=a 2a = a 2 = 1 valid?...
a=b
a^2 = ab
a^2-b^2 = ab-b^2
(a+b)(a-b) = b(a-b)
(a+b)=b
(a+a)=a
2a = a
2 = 1
valid?
No, because a-b equals zero, therefore you are dividing by zero which is a no-no. Its like saying zero times three equals zero times four, cancel the zeroes and you get three equals four.
Where did you get 2=1? As far as I can tell, a and b both equal 0
"Think not but that I know these things; or think
I know them not: not therefore am I short
Of knowing what I ought."
-John Milton, Paradise Regained (1671)
"Work hard and it might happen."
-XSquared
well if you said a=b=2
PJ: i see it now. cant divide by zero
This thread gets two thumbs down.
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