I have to find the measure of the largest angle in this triagnle. The triangle has sides with a measure of 121m, 173m, and 194m. It is not a right triangle because 121^2 + 173^2 != 194^2. I am not given any angles. I know the sine law, but I am not sure what steps I should take from here on out. If anyone could 'ask me the right questions' to show me how to get back on track I'd highly appreciate it.
Here's a picture of what I have so far:
sinC = h / 121
sinA = h / 121
194sinA = 121sinC (these both solve for h)
x^2 + h ^2 = 121^2
(173 - x) ^2 + h ^2 = 194 ^2
I really can't think of anything else. Is this even possible?