Okay here is a chemistry problem that I have done, I wanted to check it with other people...btw this stuff is really hard to me so don't be too critical...
there are 6.02E23 atoms of mercury in 201g of mercury, the density of mercury is 13.5g/mL. What is the volume of the same liquid, in micro m3, occupied by one atom of mercury?
My final solution:
One atom takes up:
How I solved it:
If 201g of mercury has 6.02E23 atoms, then 13.5g of mercury must have 6.02E23 / (201/13.5)
NumberOfAtoms = 6.02E23 / (201/13.5)
NumberOfAtoms = NumberOfAtoms * (1mL / NumberOfAtoms)
Do you think I'm correct? Chemistry sucks