C > C++ (humorous)

Code:

---

#include <limits.h>
#include <stdio.h>
#include <iostream.h>

int main()
{
  int C = INT_MAX;
  int C_plus_plus = C + 1;  // C_plus_plus is equivilent to C++
  if (C > C_plus_plus) {
    printf("C is greater!\n");
  } else {
    cout<<"C++ is greater!"<<endl;
  }
  return 0;
}

---

dang, c is greater

Yeah, C rules.

I prefer printf to cout.

You have an error in your code.

Code:

---


#include <limits.h>
#include <stdio.h>
#include <iostream.h>

int main()
{
  int C = (INT_MAX-1);//much better
  int C_plus_plus = C + 1;  // C_plus_plus is equivilent to C++
  if (C > C_plus_plus) {
    printf("C is greater!\n");
  } else {
    cout<<"C++ is greater!"<<endl;
  }
  return 0;
}

---

Quote:

---

Originally posted by LrdChaos

Code:

---

#include <limits.h>
#include <stdio.h>
#include <iostream.h>

int main()
{
  int C = INT_MAX;
  int C_plus_plus = C++;  // C_plus_plus is equivilent to C++
  if (C > C_plus_plus) {
    printf("C is greater!\n");
  } else {
    cout<<"C++ is greater!"<<endl;
  }
  return 0;
}

---

---

>You have an error in your code.
Not an error, it's supposed to be that way I think. The most common result of overflowing a signed integer is to wrap around back to the highest negative number. Thus making C better than C++.

Nice abuse of overflowing a signed integer, but the result won't be the same with everyone since the result of a signed integer overflow is undefined. :)

-Prelude

GASP! PROOF!

Prelude, it was a joke. If he subtracted one away from INT_MAX, it would make C++ better than C.

I think magos is the most creative. . .

int c_plus_plus = c++; :D

ooh that just made me laugh.:)