1. It's convoluTed, look here for a definition.

2. Mathworld is a good reference for mathematical topics. Here is another definition of convolution.

http://mathworld.wolfram.com/Convolution.html

3. The reason i want to know this is to find the length of a line, unless some1 knows a way to not use sqrt

4. Why do you want to use sqrt() to find the length of a line? What line?

5. ill post my basic code
Code:
```FOR a = 1 TO SQRT((x1 - x) + (y1 - y))
x = x + .5
y = (y + ((y1 - y) / (x1 - x) / 2))
DOT x, y
NEXT```
Not using the sqr route the line would be to long or too short

6. Calculating the length of a line. You mean the theorem of Pythagoras?
http://mathworld.wolfram.com/PythagoreanTheorem.html

Back to the original question:

>I'm not neccessarily looking to find out how to do it (I could
>easily find the answer myself), but to see if someone knows the
>formula for it. My math teahcer said she used to know, but she
>hasn't used it in so long that she forgot what it is.

The same with me. I learned it in the math lessons at university, but it is a long time ago that I did that, like some other math I currently don't use much anymore. If I would see the algorithm I will probably understand it again, but I currently don't remember how to do it.

7. Use sin cos or tan if you don't wish to use the square root function.

8. How do i use cos() to do it??

9. Do you know any of the other lengths and or angles?

10. The above code will plot a line from x,y to x1,y1

11. Then all you need to do is take the arctan of opposite side/ adjacent side to get an angle then use cos or sin with the appropiate length of one of the sides.

why in the world do you want to do this without using a sqrt function?

12. You confuse me, i never use geometry exept for my circle() function

13. Do you know any trig.?

14. i cant use -metery

15. That sucks, why not?