While swapping a hard drive in one of my machines the other day and read the lable on it. Along with the standard performance data and settings there was a notice.
"Warning! Do not expose this unit to forces in excess of 75 G"
While swapping a hard drive in one of my machines the other day and read the lable on it. Along with the standard performance data and settings there was a notice.
"Warning! Do not expose this unit to forces in excess of 75 G"
Monday - what a way to spend a seventh of your life
I've seen that too...
Stands to reason that if you and your hard drive were exposed to that much force, you'd have a lot more to worry about that keeping your HD safe.
Does anything really produce *that* much G force? (besides, say, Jupiter)
-Govtcheez
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Where might one encounter more than that?
I am thinking that it would have to be something that did not have people on board.
Maybe it is like the depth limits on the back of water resistant watches. It is usually some depth that very, very few people might ever achieve.
What kind of G's do jet fighters pull? Is there anything that experiences more than they do?
Some kind of centrifuge type equipment maybe?
hmmmmmmmmmm.
He is no fool who gives up what he cannot keep in order to gain what he cannot lose.
I can't think of anywhere (Jupiter's gravity is 2.5 G, btw).Where might one encounter more than that?
Think about it; even a small (107 lbs) person would weigh over 4 tons - this would surely kill you.
-Govtcheez
[email protected]
Maybe you found the answer, Theologian!
I wonder what would the force be at the bottom of the Pacific, in Gs?
-Govtcheez
[email protected]
2.5 G is 2.5 times the acceleration caused by gravity at the surface of the earth. One who weighs 100 pounds at 1 G will weight 250 pounds at 2.5 G.
IIRC, jet fighters approach 10 Gs at their tightest turns.
Right, I know that. I meant that at 75G someone weighing 107 lbs would weight 4 tons, not at 2.5G (unless you weren't criticizing, in which case I'll slink away)One who weighs 100 pounds at 1 G will weight 250 pounds at 2.5 G.
-Govtcheez
[email protected]
Oh.. misread the post. Thought you meant they would weigh > 4 tons at 2.5 Gs.
>IIRC, jet fighters approach 10 Gs at their tightest turns.
New Russian and US fighters pull aroung 12+ G's
75 G's hmm........................... why is that even on there?
You really wouldn't look at it that way.Originally posted by Govtcheez
Maybe you found the answer, Theologian!
I wonder what would the force be at the bottom of the Pacific, in Gs?
The concern at the bottom of the pacific would be one involving pressure whereas G's are associated with acceleration. I was just thinking that this would be similar in that the limit is theoretical rather than tested.
Based on what's been posted so far- it looks like the 75 G limit is one that has been calculated, not tested.
I've been trying to think of what pulls Gs. Fighters come to mind because they accelerate hard and I worked on them. Rockets pull some but I don't think anything like 75.
The only other thing I can think of is small machinery rotating at a high speed. Research equipment or something.
I've never seen this on a HD before but I think that it is really interesting. May have to do some more investigating- contact some manufacturers.
He is no fool who gives up what he cannot keep in order to gain what he cannot lose.
If you drop the harddrive in the concrete floor it will go from fairly high speed to 0 in a couple of mm. That would produce a very high G force. Why they choose to frase it in G's I don't get. How about a label saying " Don't drop the hard drive on the floor"
~Barjor
Ok I am back after some work with the old pen and paper (yeap I still have them) If you drop the hard drive from 1 m. I then assumed it deaccelerate in 2 mm (landing flat on the back) That would produce 500G. To make it under 75 G it would have to stop on 13 mm (1/2")
What do you mean by "deaccelerate in 2 mm? "
Shouldn't you be measuring the deacceleation in time rather than distance?
Well deacceleration is measured in m/s*s (don't know hot to make a square thingy in here) My assumption was that it take the hard drive 2 mm to come to a complete stop due to deflection in the floor and hard drive. That can be recalculated to the time it take for the hard drive to stop.
~Barjor
