Thread: sin and cosin

  1. #16
    Registered User Aran's Avatar
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    i didn't completely read all the posts in this thread, but:

    you can use the law of sines and the law of cosines to find the missing sides if you get a side and an angle....

    law of sines:
    A/sin(a) = B/sin(b) = C/sin(c)

    where segment A is oposite angle a, so on, so forth.

    i can't quite remember the law of cosines....

  2. #17
    Registered User Commander's Avatar
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    Code:
    a^2 = b^2 + c^2 - (2bc)cos(A)
    this is the cosine law
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  3. #18
    Registered User Jet_Master's Avatar
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    dont worry too much if you dont understand it...
    you dont need it till at least a couple years... and you will learn it in detail in grade 10.

    just wait it out
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  4. #19
    Registered User Commander's Avatar
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    good advice!, but didn't u hear the kid? he want's to know it NOW, so he could get ahead of the class
    ( I learned sin and cos in the begining of gr 8 though ) but one thing jet_master said was true....wait it out....it gets easier the older u get
    oh i'm sorry! i didn;t realize my fist was rushing to meet ur face!

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  5. #20
    "The Oldest Member Here" Xterria's Avatar
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    thanks for all your advice guys...I'm going to try and desipher what you said...
    i know that the cos and sin are ratios with the sides of the triangles, but so what if i know what the values are? What can i do once i get the value of sin and cosine?
    thanks

  6. #21
    back? dbaryl's Avatar
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    Well, say you know that the side opposite an angle is 2 and the hypotenuse is 5, this means that sine (opposite/hypotenuse) is 2/5 or 0.4. Now, to find the angle measure all you do is use the inverce function of sine, (written as sin-1).

    What we know:

    sin (angle) = 0.4
    (angle) = ?
    (angle) = sin-1 (0.4)


    In a scientific calculator, the values for sine of all the angles are stored, so this is essentially asking for the angle whose sine is 0.4. Most of the time you press the [shift] or [2nd] key + [sin] key to get to [sin-1]

    Like so: [shift] [sin] [0][.][4] [=] 23.578 degrees.

    So, we know that each angle has it's own ratio for sine, cosine and tangent. While we could (theotetically) memorize all these values, the calculator does it for us. In order to get to the angle from sin, cos or tan you just use the inverse functions [sin-1, cos-1 or tan-1]. These are also referred to as arcsine, arccosine, arctangent [arcsin, arccos, arctan], same function, different name.
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  7. #22
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    >i know that the cos and sin are ratios with the sides of the
    >triangles, but so what if i know what the values are? What can i
    >do once i get the value of sin and cosine?

    If you treat the cosine as being the function of a wave with representation

    y = cos (t)

    then you know what the amplitude of the wave will be at time t.

    Perhaps a little too advanced, but to give an idea of what you can use sine and cosine also for: A periodic signal can be written as the sum of, when necessary infinite, sines and cosines.

  8. #23
    Registered User toaster's Avatar
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    Originally posted by ygfperson
    the sine and cosine (and tangent, cotangent, cosecant, secant, and hyperbolic) functions are the sums of infinite numbers. their use is in relating a side of a triangle to its angle. it can also be used in circles and repeating waves because of their resemblance to triangles.

    an example of an infinite series is pi (which is related to arctangent.)
    PI/4 = 1/1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 ......
    ygfperson, don't lead him to series in calc just yet.

    Xterria, just play around with those functions in math.h using loops as an introduction.

  9. #24
    Registered User Dual-Catfish's Avatar
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    Don't forget csc, cot and sec! We learned about these crazy things today.

    Questions like, Prove:

    sin(x) + 1 - cos(x)sec(x) = cos^3(x)
    (Just an example, it probably won't work out)

  10. #25
    My diaper's full....... stevey's Avatar
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  11. #26
    Ethereal Raccoon Procyon's Avatar
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    A good way to investigate it would be through programming. For example try these test programs (susbstituting whatever your pixel drawing command is for putpixel.)

    Code:
    float t;
    for (t = 0; t < 3.14 * 2; t += 0.01)
    {
      putpixel(200 + cos(t),200 + sin(t));
    }
    Code:
    float t;
    for (t = 0; t < 3.14 * 2; t += 0.01)
    {
      putpixel(100 * t, 200 + 100 * sin(t));
    }
    Code:
    float t;
    for (t = 0; t < 3.14 * 2; t += 0.01)
    {
      printf("%f %f\n", t, sin(t)*sin(t) + cos(t)*cos(t));
    }
    Code:
    float t;
    for (t = 0; t < 3.14 * 2; t += 0.01)
    {
      printf("%f %f %f\n", t, sin(t), cos(t + 3.14/2));
    }

  12. #27
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    Questions like, Prove:

    sin(x) + 1 - cos(x)sec(x) = cos^3(x)
    It does not work out. It simplifies to sin(x)+1=cos^3(x)
    I would also advise you to wait. As someone said, you get incredibly sick of them incredibly fast. Trig is pretty boring stuff until you get to calculus.
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